Among
(S1): n → ∞ lim n 2 1 ( 2 + 4 + 6 + ⋯ + 2 n ) = 1
(S2) : n → ∞ lim n 16 1 ( 1 15 + 2 15 + 3 15 + ⋯ + n 15 ) = 16 1
A. Only (S1) is true B. Both (S1) and (S2) are true C. Both (S1) and (S2) are false D. Only (S2) is true Show answer Answer: B
If x → 0 lim 1 − c o s ( 2 x ) e a x − c o s ( b x ) − 2 c x e − c x = 17 , then 5 a 2 + b 2 is equal to
A. 64 B. 68 C. 72 D. 76 Show answer Answer: B
Let [ x ] be the greatest integer ≤ x . Then the number of points in the interval ( − 2 , 1 ) , where the function f ( x ) = ∣ [ x ] ∣ + x − [ x ] is discontinuous, is _________.
Show answer Answer: 2
If f : R → R be a continuous function satisfying ∫ 0 2 π f ( sin 2 x ) sin x d x + α ∫ 0 4 π f ( cos 2 x ) cos x d x = 0 , then the value of α is :
A. − 3 B. 2 C. − 2 D. 3 Show answer Answer: C
Let f : ( − 2 , 2 ) → R be defined by
f ( x ) = { x [ x ] , ( x − 1 ) [ x ] , − 2 < x < 0 0 ≤ x < 2
where [ x ] denotes the greatest integer function. If m and n respectively are the number of points in ( − 2 , 2 ) at which y = ∣ f ( x ) ∣ is not continuous and not differentiable, then m + n is equal to _________.
Show answer Answer: 4
Let f be a continuous function satisfying ∫ 0 t 2 ( f ( x ) + x 2 ) d x = 3 4 t 3 , ∀ t > 0 . Then f ( 4 π 2 ) is equal to :
A. − π ( 1 + 16 π 3 ) B. π ( 1 − 16 π 3 ) C. − π 2 ( 1 + 16 π 2 ) D. π 2 ( 1 − 16 π 2 ) Show answer Answer: B
lim x → 0 ( ( c o s 3 ( 4 x ) 1 − c o s 2 ( 3 x ) ) ( ( l o g e ( 2 x + 1 ) ) 5 s i n 3 ( 4 x ) ) ) is equal to ___________.
A. 15 B. 18 C. 9 D. 24 Show answer Answer: B
Let I ( x ) = ∫ x ( 1 + x e x ) 2 ( x + 1 ) d x , x > 0 . If lim x → ∞ I ( x ) = 0 , then I ( 1 ) is equal to :
A. e + 2 e + 1 − log e ( e + 1 ) B. e + 2 e + 1 + log e ( e + 1 ) C. e + 1 e + 2 − log e ( e + 1 ) D. e + 1 e + 2 + log e ( e + 1 ) Show answer Answer: C
If α > β > 0 are the roots of the equation a x 2 + b x + 1 = 0 , and
lim x → α 1 ( 2 ( 1 − a x ) 2 1 − c o s ( x 2 + b x + a ) ) 2 1 = k 1 ( β 1 − α 1 ) , then k is equal to :
A. 2 β B. β C. α D. 2 α Show answer Answer: D
n → ∞ lim { ( 2 2 1 − 2 3 1 ) ( 2 2 1 − 2 5 1 ) … ( 2 2 1 − 2 2 n + 1 1 ) } is equal to :
A. 2 B. 1 C. 2 1 D. 0 Show answer Answer: D
Let f ( x ) = ( 1 + x n ) n 1 x , x ∈ R − { − 1 } , n ∈ N , n > 2 .
If f n ( x ) = ( f ∘ f ∘ f … upto n times ) ( x ) , then
lim n → ∞ ∫ 0 1 x n − 2 ( f n ( x ) ) d x is equal to ____.
Show answer Answer: 0
lim x → ∞ ( x + x 2 − 1 ) 6 + ( x − x 2 − 1 ) 6 ( 3 x + 1 + 3 x − 1 ) 6 + ( 3 x + 1 − 3 x − 1 ) 6 x 3
A. is equal to 9 B. is equal to 2 27 C. does not exist D. is equal to 27 Show answer Answer: D
lim x → 0 x 4 48 ∫ 0 x t 6 + 1 t 3 d t is equal to ____.
Show answer Answer: 12
Let y = f ( x ) be the solution of the differential equation y ( x + 1 ) d x − x 2 d y = 0 , y ( 1 ) = e . Then x → 0 + lim f ( x ) is equal to
A. e 2 B. 0 C. e 2 1 D. e 1 Show answer Answer: B
Let x = 2 be a root of the equation x 2 + p x + q = 0 and f ( x ) = { ( x − 2 p ) 4 1 − c o s ( x 2 − 4 p x + q 2 + 8 q + 16 ) , 0 , x = 2 p x = 2 p
Then x → 2 p + lim [ f ( x )] , where [ . ] denotes greatest integer function, is
A. 2 B. 1 C. 0 D. − 1 Show answer Answer: C
The value of n → ∞ lim 2 n 4 + 4 n + 3 − n 4 + 5 n + 4 1 + 2 − 3 + 4 + 5 − 6 + ..... + ( 3 n − 2 ) + ( 3 n − 1 ) − 3 n is :
A. 2 2 3 B. 2 3 ( 2 + 1 ) C. 3 ( 2 + 1 ) D. 2 2 + 1 Show answer Answer: B
If the function f ( x ) = ⎩ ⎨ ⎧ ( 1 + ∣ cos x ∣ ) ∣ c o s x ∣ λ , μ , e c o t 4 x c o t 6 x , 0 < x < 2 π x = 2 π 2 π < x < π
is continuous at x = 2 π , then 9 λ + 6 log e μ + μ 6 − e 6 λ is equal to
A. 11 B. 10 C. 8 D. 2 e 4 + 8 Show answer Answer: B
Let y = y ( t ) be a solution of the differential equation d t d y + α y = γ e − β t where, α > 0 , β > 0 and γ > 0 . Then t → ∞ lim y ( t )
A. is 0 B. is 1 C. is − 1 D. does not exist Show answer Answer: A
lim t → 0 ( 1 s i n 2 t 1 + 2 s i n 2 t 1 + … + n s i n 2 t 1 ) s i n 2 t is equal to
A. 2 n ( n + 1 ) B. n C. n 2 + n D. n 2 Show answer Answer: B
The set of all values of a for which x → a lim ([ x − 5 ] − [ 2 x + 2 ]) = 0 , where [ α ] denotes the greatest integer less than or equal to α is equal to
A. [ − 7.5 , − 6.5 ] B. ( − 7.5 , − 6.5 ] C. [ − 7.5 , − 6.5 ) D. ( − 7.5 , − 6.5 ) Show answer Answer: D