If a function f(x) defined by
f(x)=⎩⎨⎧aex+be−x,cx2,ax2+2cx,−1≤x<11≤x≤33<x≤4
be continuous for some a,b,c∈R and f′(0)+f′(2)=e, then the value of a is :
Let f be any function continuous on [a,b] and twice differentiable on (a,b). If for all x∈(a,b), f′(x)>0 and f′′(x)<0, then for any c∈(a,b), f(b)−f(c)f(c)−f(a) is greater than :
Let a function f:[0,5]→R be continuous, f(1)=3 and F be defined as :
F(x)=∫1xt2g(t)dt , where g(t)=∫1tf(u)du
Then for the function F, the point x=1 is :
Let S be the set of all functions f:[0,1]→R, which are continuous on [0, 1] and differentiable on (0, 1). Then for every f in S, there exists a c∈(0,1), depending on f, such that
Let the function, f:[−7,0]→R be continuous on [−7,0] and differentiable on (−7,0). If f(−7)=−3 and f′(x)≤2, for all x∈(−7,0), then for all such functions f, f(−1)+f(0) lies in the interval: