If α and β are the roots of the equation 375 x 2 − 25 x − 2 = 0 , then n → ∞ lim r = 1 ∑ n α r + n → ∞ lim r = 1 ∑ n β r is equal to :
A. 116 7 B. 358 29 C. 12 1 D. 346 21 Show answer Answer: C
Let f : R → R be a continuously differentiable function such that f ( 2 ) = 6 and f ′ ( 2 ) = 48 1 . If ∫ 6 f ( x ) 4 t 3 d t = ( x − 2 ) g ( x ) , then lim x → 2 g ( x ) is equal to :
A. 18 B. 36 C. 12 D. 24 Show answer Answer: A
lim x → 0 x 2 + 2 s i n x + 1 − s i n 2 x − x + 1 x + 2 s i n x is :
A. 6 B. 1 C. 3 D. 2 Show answer Answer: D
Let f ( x ) = 5 − ∣ x − 2∣ and g ( x ) = ∣ x + 1∣ , x ∈ R . If f ( x ) attains maximum value at α and g ( x ) attains minimum value at β , then lim x → − α β x 2 − 6 x + 8 ( x − 1 ) ( x 2 − 5 x + 6 ) is equal to :
A. 2 1 B. − 2 1 C. 2 3 D. − 2 3 Show answer Answer: A
If f ( x ) = ⎩ ⎨ ⎧ x s i n ( p + 1 ) x + s i n x , q , x 3/2 x + x 2 − x , x < 0 x = 0 x > 0
is continuous at x = 0, then the ordered pair (p, q) is equal to
A. ( − 2 3 , − 2 1 ) B. ( − 2 1 , 2 3 ) C. ( − 2 3 , 2 1 ) D. ( 2 5 , 2 1 ) Show answer Answer: C
Let f : R → R be differentiable at c ∈ R and f(c) = 0. If g(x) = |f(x)|, then at x = c, g is :
A. differentiable if f ′ ( c ) = 0 B. differentiable if f ′ ( c ) = 0 C. not differentiable D. not differentiable if f ′ ( c ) = 0 Show answer Answer: A
lim n → ∞ ( n 4/3 ( n + 1 ) 1/3 + n 4/3 ( n + 2 ) 1/3 + ⋯ + n 4/3 ( 2 n ) 1/3 )
is equal to :
A. 3 4 ( 2 ) 3/4 B. 4 3 ( 2 ) 4/3 − 4 3 C. 3 4 ( 2 ) 4/3 D. 4 3 ( 2 ) 4/3 − 3 4 Show answer Answer: B
If lim x → 1 x − 1 x 2 − a x + b = 5 , then a + b is equal to :
A. 1 B. - 4 C. - 7 D. 5 Show answer Answer: C
If the function f defined on, ( 6 π , 3 π ) by
f ( x ) = { c o t x − 1 2 c o s x − 1 , k , x = 4 π x = 4 π
is continuous, then k is equal to
A. 1 B. 1/ 2 C. 2 1 D. 2 Show answer Answer: C
If f : R → R is a differentiable function and f(2) = 6,
then x → 2 lim ( x − 2 ) ∫ 6 f ( x ) 2 t d t is :-
A. 2f'(2) B. 24f'(2) C. 0 D. 12f'(2) Show answer Answer: D
If the function f ( x ) = { a ∣ π − x ∣ + 1 , x ≤ 5 b ∣ x − π ∣ + 3 , x > 5 is continuous at x = 5 , then the value of a − b is :-
A. π − 5 2 B. 5 − π 2 C. π + 5 − 2 D. π + 5 2 Show answer Answer: B
Let f : R → R be a differentiable function satisfying f ′ ( 3 ) + f ′ ( 2 ) = 0 .
Then x → 0 lim ( 1 + f ( 2 − x ) − f ( 2 ) 1 + f ( 3 + x ) − f ( 3 ) ) x 1 is equal to
A. e B. e 2 C. e − 1 D. 1 Show answer Answer: D
Let f : [ − 1 , 3 ] → R be defined as
f ( x ) = ⎩ ⎨ ⎧ ∣ x ∣ + [ x ] , x + ∣ x ∣ , x + [ x ] , − 1 ≤ x < 1 1 ≤ x < 2 2 ≤ x ≤ 3
where [t] denotes the greatest integer less than or equal to t. Then, f is discontinuous at:
A. only three points B. four or more points C. only two points D. only one point Show answer Answer: A
Let f and g be continuous functions on [ 0 , a ] such that f ( x ) = f ( a − x ) and g ( x ) + g ( a − x ) = 4 , then ∫ 0 a f ( x ) g ( x ) d x is equal to :
A. 4 ∫ 0 a f ( x ) d x B. − 3 ∫ 0 a f ( x ) d x C. ∫ 0 a f ( x ) d x D. 2 ∫ 0 a f ( x ) d x Show answer Answer: D
lim x → π /4 c o s ( x + 4 π ) c o t 3 x − t a n x is :
A. 8 2 B. 4 C. 4 2 D. 8 Show answer Answer: D
lim x → 1 − 1 − x π − 2 s i n − 1 x is equal to :
A. π 2 B. 2 π 1 C. 2 π D. π Show answer Answer: A
lim n → ∞ ( n 2 + 1 2 n + n 2 + 2 2 n + n 2 + 3 2 n + ⋯ + 5 n 1 ) is equal to :
A. tan − 1 ( 2 ) B. tan − 1 ( 3 ) C. 4 π D. 2 π Show answer Answer: A
lim x → 0 s i n 2 x c o t 2 ( 2 x ) x c o t ( 4 x ) is equal to :
A. 0 B. 4 C. 1 D. 2 Show answer Answer: C
y → 0 lim y 4 1 + 1 + y 4 − 2
A. exists and equals 2 2 1 B. exists and equals 4 2 1 C. exists and equals 2 2 ( 1 + 2 ) 1 D. does not exist Show answer Answer: B