Periodic Table · JEE Main previous year questions

2022 5 questions

1. Q742022 · 28 Jul 2022 · Shift 2

   The correct decreasing order for metallic character is :

   1. A.Na > Mg > Be > Si > P
   2. B.P > Si > Be > Mg > Na
   3. C.Si > P > Be > Na > Mg
   4. D.Be > Na > Mg > Si > P
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   Answer: A

2. Q632022 · 26 Jul 2022 · Shift 1

   Given two statements below : Statement I : In $\mathrm{C}{\mathrm{l}}_2$ molecule the covalent radius is double of the atomic radius of chlorine. Statement II : Radius of anionic species is always greater than their parent atomic radius. Choose the most appropriate answer from options given below :

   1. A.Both Statement I and Statement II are correct.
   2. B.Both Statement I and Statement II are incorrect.
   3. C.Statement I is correct but Statement II is incorrect.
   4. D.Statement I is incorrect but Statement II is correct.
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   Answer: D

3. Q652022 · 25 Jul 2022 · Shift 2

   The first ionization enthalpies of Be, B, N and O follow the order

   1. A.O < N < B < Be
   2. B.Be < B < N < O
   3. C.B < Be < N < O
   4. D.B < Be < O < N
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   Answer: D

4. Q632022 · 27 Jun 2022 · Shift 2

   The correct order of increasing ionic radii is

   1. A.${\text{Mg}}^{2+}<{\text{Na}}^{+}<{\text{F}}^{-}<{\text{O}}^{2-}<{\text{N}}^{3-}$
   2. B.${\text{N}}^{3-}<{\text{O}}^{2-}<{\text{F}}^{-}<{\text{Na}}^{+}<{\text{Mg}}^{2+}$
   3. C.${\text{F}}^{-}<{\text{Na}}^{+}<{\text{O}}^{2-}<{\text{Mg}}^{2+}<{\text{N}}^{3-}$
   4. D.${\text{Na}}^{+}<{\text{F}}^{-}<{\text{Mg}}^{2+}<{\text{O}}^{2-}<{\text{N}}^{3-}$
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   Answer: A

5. Q762022 · 26 Jun 2022 · Shift 1

   The correct order of melting points of hydrides of group 16 elements is :

   1. A.${\mathrm{H}}_2\mathrm{S}<{\mathrm{H}}_2\mathrm{Se}<{\mathrm{H}}_2\mathrm{Te}<{\mathrm{H}}_2\mathrm{O}$
   2. B.${\mathrm{H}}_2\mathrm{O}<{\mathrm{H}}_2\mathrm{S}<{\mathrm{H}}_2\mathrm{Se}<{\mathrm{H}}_2\mathrm{Te}$
   3. C.${\mathrm{H}}_2\mathrm{S}<{\mathrm{H}}_2\mathrm{Te}<{\mathrm{H}}_2\mathrm{Se}<{\mathrm{H}}_2\mathrm{O}$
   4. D.${\mathrm{H}}_2\mathrm{Se}<{\mathrm{H}}_2\mathrm{S}<{\mathrm{H}}_2\mathrm{Te}<{\mathrm{H}}_2\mathrm{O}$
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   Answer: A