Periodic Table · JEE Main previous year questions

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2020 12 questions

Q652020 · 6 Sept 2020 · Shift 1
The set that contains atomic numbers of only transition elements, is :
1. A.21, 32, 53, 64
2. B.9, 17, 34, 38
3. C.37, 42, 50, 64
4. D.21, 25, 42, 72
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Answer: D
Q732020 · 6 Sept 2020 · Shift 2· Numerical answer
The atomic number of Unnilunium is _______.
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Answer: 101
Q612020 · 3 Sept 2020 · Shift 1
The atomic number of the element unnilennium is :
1. A.109
2. B.102
3. C.119
4. D.108
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Answer: A
Q512020 · 3 Sept 2020 · Shift 2
Among the statements (I – IV), the correct ones are: (I) Be has smaller atomic radius compared to Mg. (II) Be has higher ionization enthalpy than Al. (III) Charge/radius ratio of Be is greater than that of Al. (IV) Both Be and Al form mainly covalent compounds.
1. A.(I), (II) and (IV)
2. B.(II), (III) and (IV)
3. C.(I), (III) and (IV)
4. D.(I), (II) and (III)
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Answer: A
Q562020 · 3 Sept 2020 · Shift 2
The five successive ionization enthalpies of an element are 800, 2427, 3658, 25024 and $32824 kJ mo l^{- 1}$ . The number of valence electrons in the element is :
1. A.2
2. B.3
3. C.4
4. D.5
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Answer: B
Q512020 · 2 Sept 2020 · Shift 2
Three elements X, Y and Z are in the $3^{rd}$ period of the periodic table. The oxides of X, Y and Z, respectively, are basic, amphoteric and acidic. The correct order of the atomic numbers of X, Y and Z is :
1. A. $X < Z < Y$
2. B. $Y < X < Z$
3. C. $Z < Y < X$
4. D. $X < Y < Z$
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Answer: D
Q592020 · 9 Jan 2020 · Shift 1
B has a smaller first ionization enthalpy than Be. Consider the following statements : (I) It is easier to remove 2p electron than 2s electron (II) 2p electron of B is more shielded from the nucleus by the inner core of electrons than the 2s electrons of Be. (III) 2s electron has more penetration power than 2p electron. (IV) atomic radius of B is more than Be (Atomic number B = 5, Be = 4) The correct statements are :
1. A.(I), (III) and (IV)
2. B.(II), (III) and (IV)
3. C.(I), (II) and (IV)
4. D.(I), (II) and (III)
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Answer: D
Q632020 · 8 Jan 2020 · Shift 1
For the Balmer series in the spectrum of H atom, $\overset{ν}{ˉ} = R_{H} {\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}}}$ , the correct statements among (I) to (IV) are : (I) As wavelength decreases, the lines in the series converge (II) The integer $n_{1}$ is equal to 2 (III) The line of longest wavelength corresponds to $n_{2} = 3$ (IV) The ionization energy of hydrogen can be calculated from wave number of these lines
1. A.(II), (III), (IV)
2. B.(I), (II), (III)
3. C.(I), (III), (IV)
4. D.(I), (II), (IV)
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Answer: B
Q652020 · 8 Jan 2020 · Shift 1
The first ionization energy (in kJ/mol) of Na, Mg, Al and Si respectively, are :
1. A.496, 577, 786, 737
2. B.496, 737, 577, 786
3. C.786, 737, 577, 496
4. D.496, 577, 737, 786
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Answer: B
Q542020 · 8 Jan 2020 · Shift 2
The increasing order of the atomic radii of the following elements is :- (a) C (b) O (c) F (d) Cl (e) Br
1. A.(a) < (b) < (c) < (d) < (e)
2. B.(c) < (b) < (a) < (d) < (e)
3. C.(b) < (c) < (d) < (a) < (e)
4. D.(d) < (c) < (b) < (a) < (e)
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Answer: B
Q702020 · 8 Jan 2020 · Shift 2
For the following Assertion and Reason, the correct option is Assertion : For hydrogenation reactions, the catalytic activity increases from Group 5 to Group 11 metals with maximum activity shown by Group 7-9 elements. Reason : The reactants are most strongly adsorbed on group 7-9 elements.
1. A.Both assertion and reason are true and the reason is the correct explanation for the assertion.
2. B.The assertion is true, but the reason is false.
3. C.Both assertion and reason are true but the reason is not the correct explanation for the assertion.
4. D.Both assertion and reason are false.
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Answer: B
Q542020 · 7 Jan 2020 · Shift 1
The atomic radius of Ag is closed to :
1. A.Au
2. B.Cu
3. C.Hg
4. D.Ni
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Answer: A