Differential Equations · JEE Advanced previous year questions

2025 1 question

1. Q92025 · 18 May 2025 · Paper 2· Numerical answer

   Let $y(x)$ be the solution of the differential equation $$x^2\frac{dy}{dx}+xy=x^2+y^2,x>\frac{1}{e},$$ satisfying $y(1)=0$. Then the value of $2\frac{(y(e){)}^2}{y(e^2)}$ is ____.

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   Answer: 0.7 to 0.8