Permutations & Combinations · NDA previous year questions

2016 3 questions

1. Q272016 · 18 Sept 2016

   A five-digit number divisible by 3 is to be formed using the digits 0, 1, 2, 3 and 4 without repetition of digits. What is the number of ways this can be done ?

   1. A.96
   2. B.48
   3. C.32
   4. D.No number can be formed
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   Answer: D

2. Q282016 · 18 Sept 2016

   What is ${}^{47}{C}_4+{}^{51}{C}_3+{\sum }_{j=2}^5{}^{52-j}{C}_3$ equal to ?

   1. A.${}^{52}{C}_4$
   2. B.${}^{51}{C}_5$
   3. C.${}^{53}{C}_4$
   4. D.${}^{52}{C}_5$
   Show answer

   Answer: A

3. Q142016 · 17 Apr 2016

   What is the number of ways in which 3 holiday travel tickets are to be given to 10 employees of an organization, if each employee is eligible for any one or more of the tickets?

   1. A.60
   2. B.120
   3. C.500
   4. D.1000
   Show answer

   Answer: D