Laws of Motion & Friction · JEE Main previous year questions

2010 2 questions

1. Q372010 · 25 Apr 2010 · Shift 1
   
   1. A.$4.9\mathrm{m}{\mathrm{s}}^{-2}$ in horizontal direction
   2. B.$9.8\mathrm{m}{\mathrm{s}}^{-2}$ in vertical direction
   3. C.Zero
   4. D.$4.9\mathrm{m}{\mathrm{s}}^{-2}$ in vertical direction
   Show answer

   Answer: D

2. Q392010 · 25 Apr 2010 · Shift 1

   The equation of a wave on a string of linear mass density $0.04\mathrm{kg}{\mathrm{m}}^{-1}$ is given by $$y=0.02(\mathrm{m})\sin \left[2\pi \left(\frac{t}{0.04(\mathrm{s})}-\frac{x}{0.50(\mathrm{m})}\right)\right].$$ The tension in the string is

   1. A.$4.0\mathrm{N}$
   2. B.$12.5\mathrm{N}$
   3. C.$0.5\mathrm{N}$
   4. D.$6.25\mathrm{N}$
   Show answer

   Answer: D