Trigonometry · JEE Main previous year questions

2010 2 questions

1. Q12010 · 25 Apr 2010 · Shift 1

   Let $\cos (\alpha +\beta )=\frac{4}{5}$ and $\sin (\alpha -\beta )=\frac{5}{13}$, where $0\le \alpha ,\beta \le \frac{\pi }{4}$. Then $\tan 2\alpha =$

   1. A.$\frac{56}{33}$
   2. B.$\frac{19}{12}$
   3. C.$\frac{20}{7}$
   4. D.$\frac{25}{16}$
   Show answer

   Answer: A

2. Q152010 · 25 Apr 2010 · Shift 1

   The area bounded by the curves $y=\cos x$ and $y=\sin x$ between the ordinates $x=0$ and $x=\frac{3\pi }{2}$ is

   1. A.$4\sqrt{2}+2$
   2. B.$4\sqrt{2}-1$
   3. C.$4\sqrt{2}+1$
   4. D.$4\sqrt{2}-2$
   Show answer

   Answer: D