Let S be the set of all α ∈ R such that the equation, cos 2 x + α sin x = 2 α − 7 has a solution. Then S is equal to :
A. [ 2 , 6 ] B. [ 3 , 7 ] C. [ 1 , 4 ] D. R Show answer Answer: A
Let f ( x ) = e x − x and g ( x ) = x 2 − x , ∀ x ∈ R . Then the set of all x ∈ R , where the function h ( x ) = ( f ∘ g ) ( x ) is increasing, is :
A. [ 0 , ∞ ) B. [ − 1 , − 2 1 ] ∪ [ 2 1 , ∞ ) C. [ − 2 1 , 0 ] ∪ [ 1 , ∞ ) D. [ 0 , 2 1 ] ∪ [ 1 , ∞ ) Show answer Answer: D
Let f ( x ) = log e ( sin x ) , ( 0 < x < π ) and g ( x ) = sin − 1 ( e − x ) , ( x ≥ 0 ) . If α is a positive real number such that a = (fog)'(α ) and b = (fog)(α ), then :
A. a α 2 + b α − a = − 2 α 2 B. a α 2 + b α + a = 0 C. a α 2 − b α − a = 0 D. a α 2 − b α − a = 1 Show answer Answer: D
If f(x) is a non-zero polynomial of degree four, having local extreme points at x = –1, 0, 1; then the set
S = { x ∈ R : f ( x ) = f ( 0 )}
Contains exactly :
A. four rational numbers. B. four irrational numbers. C. two irrational and one rational number. D. two irrational and two rational numbes. Show answer Answer: C
All the points in the set
S = { α − i α + i : α ∈ R } ( i = − 1 ) lie on a :
A. straight line whose slope is –1 B. straight line whose slope is 1. C. circle whose radius is 1. D. circle whose radius is 2 . Show answer Answer: C
Let f ( x ) = 15 − ∣ x − 10∣ ; x ∈ R . Then the set of all values of x, at which the function, g ( x ) = f ( f ( x )) is not differentiable, is :
A. {10,15} B. {5,10,15,20} C. {10} D. {5,10,15} Show answer Answer: D
Let k = 1 ∑ 10 f ( a + k ) = 16 ( 2 10 − 1 ) where the function f satisfies
f ( x + y ) = f ( x ) f ( y ) for all natural numbers x, y and f(1) = 2. then the natural number 'a' is
A. 2 B. 16 C. 4 D. 3 Show answer Answer: D
If the function f : R − { 1 , − 1 } → A defined by
f ( x ) = 1 − x 2 x 2 , is surjective, then A is equal to
A. R − (−1, 0) B. R − {−1} C. R − [−1, 0) D. [ 0 , ∞ ) Show answer Answer: C
Let S be the set of all values of x for which the tangent to the curve
y = f ( x ) = x 3 − x 2 − 2 x at (x, y) is parallel to the line segment joining the points (1, f(1)) and (−1, f(−1)), then S is equal to :
A. { 3 1 , − 1 } B. { − 3 1 , 1 } C. { − 3 1 , − 1 } D. { 3 1 , 1 } Show answer Answer: B
If f ( x ) = [ x ] − [ 4 x ] , x ∈ 4 , where [ x ] denotes the greatest integer function, then
A. Both lim x → 4 − f ( x ) and lim x → 4 + f ( x ) exist but are not equal B. f is continuous at x = 4 C. lim x → 4 + f ( x ) exists but lim x → 4 − f ( x ) does not existD. lim x → 4 − f ( x ) exists but lim x → 4 + f ( x ) does not existShow answer Answer: B
The domain of the definition of the function
f ( x ) = 4 − x 2 1 + log 10 ( x 3 − x ) is
A. ( − 1 , 0 ) ∪ ( 1 , 2 ) ∪ ( 2 , ∞ ) B. ( − 2 , − 1 ) ∪ ( − 1 , 0 ) ∪ ( 2 , ∞ ) C. ( 1 , 2 ) ∪ ( 2 , ∞ ) D. ( − 1 , 0 ) ∪ ( 1 , 2 ) ∪ ( 3 , ∞ ) Show answer Answer: A
Let f ( x ) = a x ( a > 0 ) be written as
f ( x ) = f 1 ( x ) + f 2 ( x ) , where f 1 ( x ) is an even function and f 2 ( x ) is an odd function.
Then f 1 ( x + y ) + f 1 ( x − y ) equals
A. 2 f 1 ( x ) f 1 ( y ) B. 2 f 1 ( x + y ) f 1 ( x − y ) C. 2 f 1 ( x ) f 2 ( y ) D. 2 f 1 ( x + y ) f 2 ( x − y ) Show answer Answer: A
Let f ( x ) = ∫ 0 x g ( t ) d t where g is a non-zero even function. If f ( x + 5 ) = g ( x ) , then ∫ 0 x f ( t ) d t equals-
A. 5 ∫ x + 5 5 g ( t ) d t B. ∫ x + 5 5 g ( t ) d t C. ∫ 5 x + 5 g ( t ) d t D. 2 ∫ 5 x + 5 g ( t ) d t Show answer Answer: B
Let S = { 1 , 2 , 3 , … , 100 } . The number of non-empty subsets A of S such that the product of elements in A is even is :
A. 2 50 − 1 B. 2 50 ( 2 50 − 1 ) C. 2 100 − 1 D. 2 50 + 1 Show answer Answer: B
Considering only the principal values of inverse functions, the set
A = { x ≥ 0 : tan − 1 ( 2 x ) + tan − 1 ( 3 x ) = 4 π }
A. contains two elements B. contains more than two elements C. is an empty set D. is a singleton Show answer Answer: D
Let S be the set of all points in ( − π , π ) at which the function, f ( x ) = min { sin x , cos x } is not differentiable. Then S is a subset of which of the following ?
A. { − 2 π , − 4 π , 4 π , 2 π } B. { − 4 3 π , − 2 π , 2 π , 4 3 π } C. { − 4 π , 0 , 4 π } D. { − 4 3 π , − 4 π , 4 3 π , 4 π } Show answer Answer: D
Let Z be the set of integers.
If A = { x ∈ Z : 2 ( x + 2 ) ( x 2 − 5 x + 6 ) = 1 } and
B = { x ∈ Z : − 3 < 2 x − 1 < 9 } ,
then the number of subsets of the set A × B , is
A. 2 12 B. 2 18 C. 2 10 D. 2 15 Show answer Answer: D
If the function f given by f ( x ) = x 3 − 3 ( a − 2 ) x 2 + 3 a x + 7 , for some a ∈ R is increasing in ( 0 , 1 ] and decreasing in [ 1 , 5 ) , then a root of the equation, ( x − 1 ) 2 f ( x ) − 14 = 0 ( x = 1 ) is :
A. − 7 B. 5 C. 7 D. 6 Show answer Answer: C
Let f be a differentiable function such that f ( 1 ) = 2 and f ′ ( x ) = f ( x ) for all x ∈ R . If h ( x ) = f ( f ( x )) , then h ′ ( 1 ) is equal to :
A. 4 e B. 2 e 2 C. 4 e 2 D. 2 e Show answer Answer: A
The set of all values of λ for which the system of linear equations
x − 2 y − 2 z = λ x
x + 2 y + z = λ y
− x − y = λ z
has a non-trivial solution :
A. is an empty set B. contains more than two elements C. is a singleton D. contains exactly two elements Show answer Answer: C
Let K be the set of all real values of x where the function f ( x ) = sin ∣ x ∣ − ∣ x ∣ + 2 ( x − π ) cos ∣ x ∣ is not differentiable. Then the set K is equal to :
A. { 0 , π } B. ϕ (an empty set)C. { r } D. { 0 } Show answer Answer: B
The number of functions f from { 1 , 2 , 3 , … , 20 } onto { 1 , 2 , 3 , … , 20 } such that f ( k ) is a multiple of 3, whenever k is a multiple of 4, is :
A. 6 5 × ( 15 )! B. 5 6 × 15 C. ( 15 )! × 6 ! D. 5 ! × 6 ! Show answer Answer: C
Let a function f : ( 0 , ∞ ) → ( 0 , ∞ ) be defined by f ( x ) = 1 − x 1 . Then f is :
A. not injective but it is surjective B. neither injective nor surjective C. injective only D. both injective as well as surjective Show answer Answer: B
Let f : R → R be a function defined as
f ( x ) = ⎩ ⎨ ⎧ 5 a + b x b + 5 x 30 ; x ≤ 1 ; 1 < x < 3 ; 3 ≤ x < 5 ; x ≥ 5
Then, f is
A. continuous if a = 0 and b = 5 B. continuous if a = − 5 and b = 10 C. continuous if a = 5 and b = 5 D. not continuous for any values of a and b Show answer Answer: D
For x ∈ R − { 0 , 1 } , Let f 1 ( x ) = x 1 , f 2 ( x ) = 1 − x and f 3 ( x ) = 1 − x 1 be three given functions. If a function, J ( x ) satisfies ( f 2 ∘ J ∘ f 1 ) ( x ) = f 3 ( x ) then J ( x ) is equal to :
A. f 1 ( x ) B. x 1 f 3 ( x ) C. f 2 ( x ) D. f 3 ( x ) Show answer Answer: D