Hydrocarbons · JEE Main previous year questions

2020 6 questions

1. Q632020 · 6 Sept 2020 · Shift 1
   
   1. A.
   2. B.
   3. C.
   4. D.
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   Answer: B

2. Q562020 · 6 Sept 2020 · Shift 2

   The correct match between Item-I (starting material) and Item-II (reagent) for the preparation of benzaldehyde is : | Item-I | Item-II | | :--- | :--- | | (I) Benzene | (P) $\mathrm{HCl}$ and $\mathrm{SnC}{\mathrm{l}}_2$, ${\mathrm{H}}_3{\mathrm{O}}^{+}$ | | (II) Benzonitrile | (Q) ${\mathrm{H}}_2$, $\mathrm{Pd}$-$\mathrm{BaS}{\mathrm{O}}_4$, S and quinoline | | (III) Benzoyl Chloride | (R) $\mathrm{CO}$, $\mathrm{HCl}$ and $\mathrm{AlC}{\mathrm{l}}_3$ |

   1. A.(I) - (R), (II) - (P) and (III) - (Q)
   2. B.(I) - (P), (II) - (Q) and (III) - (R)
   3. C.(I) - (Q), (II) - (R) and (III) - (P)
   4. D.(I) - (R), (II) - (Q) and (III) - (P)
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   Answer: A

3. Q622020 · 9 Jan 2020 · Shift 1
   
   1. A.
   2. B.
   3. C.
   4. D.
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   Answer: A

4. Q622020 · 9 Jan 2020 · Shift 2

   The reaction of ${\mathrm{H}}_3{\mathrm{N}}_3{\mathrm{B}}_3\mathrm{C}{\mathrm{l}}_3$ (A) with $\mathrm{LiB}{\mathrm{H}}_4$ in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of (A) with (C) leads to ${\mathrm{H}}_3{\mathrm{N}}_3{\mathrm{B}}_3(\mathrm{Me}{)}_3$. Compounds (B) and (C) respectively, are :

   1. A.Borazine and MeBr
   2. B.Diborane and MeMgBr
   3. C.Boron nitride and MeBr
   4. D.Borazine and MeMgBr
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   Answer: D

5. Q532020 · 8 Jan 2020 · Shift 2
   
   1. A.
   2. B.
   3. C.
   4. D.
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   Answer: C

6. Q732020 · 8 Jan 2020 · Shift 2· Numerical answer
   
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   Answer: 13