Chemical & Ionic Equilibrium · JEE Main previous year questions

277 questions asked across 20 exam years, newest first

Year-wise papers Topic-wise questions

Practise this topic

2019 19 questions

Q642019 · 12 Apr 2019 · Shift 1
What is the molar solubility of $Al(OH)_{3}$ in 0.2 M NaOH solution ? Given that, solubility product of $Al(OH)_{3} = 2.4 \times 1 0^{- 24}$ :
1. A. $3 \times 1 0^{- 22}$
2. B. $3 \times 1 0^{- 19}$
3. C. $12 \times 1 0^{- 21}$
4. D. $12 \times 1 0^{- 22}$
Show answer
Answer: A
Q792019 · 12 Apr 2019 · Shift 2
The molar solubility of $Cd(OH)_{2}$ is $1.84 \times 1 0^{- 5} M$ in water. The expected solubility of $Cd(OH)_{2}$ in a buffer solution of pH = 12 is :
1. A. $2.49 \times 1 0^{- 10} M$
2. B. $1.84 \times 1 0^{- 9} M$
3. C. $6.23 \times 1 0^{- 11} M$
4. D. $\frac{2.49}{1.84} \times 1 0^{- 9} M$
Show answer
Answer: A
Q802019 · 12 Apr 2019 · Shift 2
In which one of the following equilibria, $K_{p} \neq = K_{C}$ ?
1. A. $2 NO(g) ⇌ N_{2} (g) + O_{2} (g)$
2. B. $2 C(s) + O_{2} (g) ⇌ 2 CO(g)$
3. C. $2 HI(g) ⇌ H_{2} (g) + I_{2} (g)$
4. D. $NO_{2} (g) + SO_{2} (g) ⇌ NO(g) + SO_{3} (g)$
Show answer
Answer: B
Q702019 · 10 Apr 2019 · Shift 1
Consider the following statements (a) The pH of a mixture containing 400 mL of 0.1 M $H_{2} S O_{4}$ and 400 mL of 0.1 M NaOH will be approximately 1.3 (b) Ionic product of water is temperature dependent. (c) A monobasic acid with Ka = $1 0^{- 5}$ has pH = 5. The degree of dissociation of this acid is 50 %. (d) The Le Chatelier's principle is not applicable to common-ion effect. The correct statements are :
1. A.(a) and (b)
2. B.(a), (b) and (c)
3. C.(a), (b) and (d)
4. D.(b) and (c)
Show answer
Answer: B
Q732019 · 10 Apr 2019 · Shift 2
For the reaction, $2S O_{2} (g) + O_{2} (g) = 2S O_{3} (g)$ , $Δ H = - 57.2 kJ mo l^{- 1}$ and $K_{C} = 1.7 \times 1 0^{16}$ Which of the following statement is incorrect ?
1. A.The equilibrium will shift in forward direction as the pressure increase.
2. B.The addition of inert gas at constant volume will not affect the equilibrium constant.
3. C.The equilibrium constant is large suggestive of reaction going to completion and so no catalyst is required.
4. D.The equilibrium constant decreases as the temperature increase.
Show answer
Answer: C
Q772019 · 10 Apr 2019 · Shift 2
The pH of a 0.02 M $N H_{4} Cl$ solution will be : [given $K_{b} (N H_{4} OH) = 1 0^{- 5}$ and $lo g 2 = 0.301$ ]
1. A.2.56
2. B.5.35
3. C.4.35
4. D.4.65
Show answer
Answer: B
Q802019 · 9 Apr 2019 · Shift 2
1. A.(C)
2. B.(A)
3. C.(B)
4. D.(D)
Show answer
Answer: B
Q632019 · 8 Apr 2019 · Shift 2
For the following reactions, equilibrium constants are given : $S (s) + O_{2} (g) ⇌ S O_{2} (g)$ ; $K_{1} = 1 0^{52}$ $2S (s) + 3 O_{2} (g) ⇌ 2S O_{3} (g)$ ; $K_{2} = 1 0^{129}$ The equilibrium constant for the reaction, $2S O_{2} (g) + O_{2} (g) ⇌ 2S O_{3} (g)$ is :
1. A. $1 0^{181}$
2. B. $1 0^{25}$
3. C. $1 0^{77}$
4. D. $1 0^{154}$
Show answer
Answer: B
Q672019 · 12 Jan 2019 · Shift 1
The correct order for acid strength of compounds : $CH \equiv CH, C H_{3} - C \equiv CH$ and $C H_{2} = C H_{2}$ is as follows
1. A. $CH \equiv CH > C H_{2} = C H_{2} > C H_{3} - C \equiv CH$
2. B. $C H_{3} - C \equiv CH > C H_{2} = C H_{2} > HC \equiv CH$
3. C. $HC \equiv CH > C H_{3} - C \equiv CH > C H_{2} = C H_{2}$
4. D. $C H_{3} - CH \equiv CH > CH \equiv CH > C H_{2} = C H_{2}$
Show answer
Answer: C
Q682019 · 12 Jan 2019 · Shift 1
1. A. $C H_{3} C H_{2} COC H_{3} + PhMgX$
2. B. $PhCOC H_{3} + C H_{3} C H_{2} MgX$
3. C. $PhCOC H_{2} C H_{3} + C H_{3} MgX$
4. D. $HCHO + PhCH (C H_{3}) C H_{2} MgX$
Show answer
Answer: D
Q792019 · 12 Jan 2019 · Shift 1
In a chemical reaction, $A + 2B K 2C + D$ the initial concentration of B was 1.5 times of the concentration of A, but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant (K) for the aforesaid chemical reaction is -
1. A.16
2. B.1
3. C.1/4
4. D.4
Show answer
Answer: D
Q812019 · 12 Jan 2019 · Shift 1
Two solids dissociate as follows – $A (s) ⇌ B (g) + C (g); K_{p1} = x at m^{2}$ $D (s) ⇌ C (g) + E (g); K_{p2} = y at m^{2}$ The total pressure when both the solids dissociated simultaneously is -
1. A. $(x + y) atm$
2. B. $(x + y) atm$
3. C. $2 (x + y) atm$
4. D. $x^{2} + y^{2} atm$
Show answer
Answer: C
Q852019 · 12 Jan 2019 · Shift 1
A metal on combustion in excess air forms X. X upon hydrolysis with water yields $H_{2} O_{2}$ and $O_{2}$ along with another product. The metal is :
1. A. $Rb$
2. B. $Mg$
3. C. $Na$
4. D. $Li$
Show answer
Answer: A
Q742019 · 12 Jan 2019 · Shift 2
If $K_{s p}$ of $A g_{2} C O_{3}$ is $8 \times 1 0^{- 12}$ , the molar solubility of $A g_{2} C O_{3}$ in 0.1 M $AgN O_{3}$ is -
1. A. $8 \times 1 0^{- 12} M$
2. B. $8 \times 1 0^{- 10} M$
3. C. $8 \times 1 0^{- 13} M$
4. D. $8 \times 1 0^{- 11} M$
Show answer
Answer: B
Q752019 · 12 Jan 2019 · Shift 2
1. A.
2. B.
3. C.
4. D.
Show answer
Answer: B
Q632019 · 11 Jan 2019 · Shift 2
For the equilibrium, $2 H_{2} O ⇌ H_{3} O^{+} + O H^{-}, the value of Δ G^{\circ} at 298 K is approximately :$
1. A. $- 80 kJ mol^{- 1}$
2. B. $100 kJ mol^{- 1}$
3. C. $- 100 kJ mol^{- 1}$
4. D. $80 kJ mol^{- 1}$
Show answer
Answer: D
Q722019 · 11 Jan 2019 · Shift 2
Given the equilibrium constant: $K_{C}$ of the reaction : $Cu (s) + 2A g^{+} (aq) \to C u^{2 +} (aq) + 2Ag (s)$ is $10 \times 1 0^{15}$ , calculate the $E_{ce l l}^{0}$ of this reaction at $298 K$ $[2.303 \frac{R T}{F} at 298 K = 0.059 V]$
1. A. $0.4736 mV$
2. B. $0.04736 V$
3. C. $0.4736 V$
4. D. $0.04736 mV$
Show answer
Answer: C
Q612019 · 9 Jan 2019 · Shift 1
The correct decreasing order for acid strength is :
1. A. $N O_{2} C H_{2} COOH > FC H_{2} COOH > CNC H_{2} COOH > ClC H_{2} COOH$
2. B. $FC H_{2} COOH > NCC H_{2} COOH > N O_{2} C H_{2} COOH > ClC H_{2} COOH$
3. C. $CNC H_{2} COOH > O_{2} NC H_{2} COOH > FC H_{2} COOH > ClC H_{2} COOH$
4. D. $N O_{2} C H_{2} COOH > NCC H_{2} COOH > FC H_{2} COOH > ClC H_{2} COOH$
Show answer
Answer: D
Q762019 · 9 Jan 2019 · Shift 1
$20 mL$ of $0.1 M H_{2} S O_{4}$ solution is added to $30 mL$ of $0.2 M N H_{4} OH$ solution. The pH of the resultant mixture is : $[p K_{b} of N H_{4} OH = 4.7]$ .
1. A.5.2
2. B.9.0
3. C.5.0
4. D.9.4
Show answer
Answer: B