Coordination Compounds · JEE Main previous year questions

2010 1 question

1. Q802010 · 25 Apr 2010 · Shift 1

   A solution containing 2.675g of $\mathrm{CoC}{\mathrm{l}}_3\cdot 6N{\mathrm{H}}_3$ (molar mass = $267.5\mathrm{g}\mathrm{mo}{\mathrm{l}}^{-1}$) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of $\mathrm{AgN}{\mathrm{O}}_3$ to give 4.78 g of AgCl (molar mass = $143.5\mathrm{g}\mathrm{mo}{\mathrm{l}}^{-1}$). The formula of the complex is : (At. Mass of Ag = 108 u)

   1. A.$[\mathrm{Co}(\mathrm{N}{\mathrm{H}}_3{)}_6]\mathrm{C}{\mathrm{l}}_3$
   2. B.$[\mathrm{CoC}{\mathrm{l}}_2(\mathrm{N}{\mathrm{H}}_3{)}_4]\mathrm{Cl}$
   3. C.$[\mathrm{CoC}{\mathrm{l}}_3(\mathrm{N}{\mathrm{H}}_3{)}_3]$
   4. D.$[\mathrm{CoCl}(\mathrm{N}{\mathrm{H}}_3{)}_5]\mathrm{C}{\mathrm{l}}_2$
   Show answer

   Answer: A