Laws of Motion & Friction · JEE Advanced previous year questions

2024 3 questions

1. Q212024 · 26 May 2024 · Paper 1

   A block of mass $5\text{ kg}$ moves along the $x$-direction subject to the force $F=(-20x+10)\text{ N}$, with the value of $x$ in metre. At time $t=0\text{ s}$, it is at rest at position $x=1\text{ m}$. The position and momentum of the block at $t=(\pi /4)\text{ s}$ are

   1. A.$-0.5\text{ m},5\text{ kg m/s}$
   2. B.$0.5\text{ m},0\text{ kg m/s}$
   3. C.$0.5\text{ m},-5\text{ kg m/s}$
   4. D.$-1\text{ m},5\text{ kg m/s}$
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   Answer: C

2. Q232024 · 26 May 2024 · Paper 1· One or more correct
   
   1. A.With a node at $\mathrm{O}$, the minimum frequency of vibration of the composite string is ${\nu }_0$.
   2. B.With an antinode at $\mathrm{O}$, the minimum frequency of vibration of the composite string is $2{\nu }_0$.
   3. C.When the composite string vibrates at the minimum frequency with a node at $\mathrm{O}$, it has $6$ nodes, including the end nodes.
   4. D.No vibrational mode with an antinode at $\mathrm{O}$ is possible for the composite string.
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   Answer: A, C, D

3. Q302024 · 26 May 2024 · Paper 1· Numerical answer
   
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   Answer: 18